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Matches 1 to 2 of 2 for Last Name equals BRANDT AND Tree equals SEQUOIA

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 #  Last Name, Given Name(s)    Person ID   Born/Christened    Location   Tree | Branch 
1
BRANDT, Carl D		I68699  b. Abt 1885 , , Connecticut, United States  SEQUOIA
2
BRANDT, Eunice Wilbur		I60946  b. 1 Oct 1903 Binghamton, Broome Co, New York, United States  SEQUOIA

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